Question

How do you write an equation in point slope form given (5,-4), (1/2, -1/4)?

Answer 1

The equation of the line in slope-intercept form is `y= -5/6x + 1/6.`

Explanation:

The slope of the line passing through `(5,-4) and (1/2,-1/4)` is `m= (y_2-y_1)/(x_2-x_1)= (-1/4+4)/(1/2-5)=(15/4)/(-9/2) =-5/6`

Let the equation of the line in slope-intercept form be `y=mx+c or y=-5/6x+c` The point (5,-4) will satisfy the equation . So, `-4= -5/6*5+c or c= 25/6-4= 1/6`

Hence the equation of the line in slope-intercept form is `y= -5/6x + 1/6.` graph{-5/6x+1/6 [-10, 10, -5, 5]}[Ans]