A model train, with a mass of #5 kg#, is moving on a circular track with a radius of #3 m#. If the train's rate of revolution changes from #1/3 Hz# to #2/7 Hz#, by how much will the centripetal force applied by the tracks change by?

Question

1233 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-14T12:04:42

The change in centripetal force #=1.34N#

The centripetal force is

#F=mr omega^2#

mass is #m=5kg#

radius #r=3m#

#Delta omega=(1/3-2/7)*2pi=(2/21pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=5*3*(2/21pi)^2#

#=1.34N#