How do you write the point slope form of an equation for a lint that passes through (1,-4) with m=-8/3?

1 Answer
Apr 15, 2017

#y+4=-8/3(x-1)#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here " m=-8/3" and " (x_1,y_1)=(1,-4)#

Substitute these values into the equation.

#y-(-4)=-8/3(x-1)#

#rArry+4=-8/3(x-1)larrcolor(red)" in point-slope form"#