A model train with a mass of #4 kg# is moving along a track at #3 (cm)/s#. If the curvature of the track changes from a radius of #4 cm# to #27 cm#, by how much must the centripetal force applied by the tracks change?

Question

949 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-16T14:46:38

The centripetal force changes by #=0.077N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=4kg#

speed, #v=0.03ms^-1#

radius, #=r#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=4*0.03^2/0.04=0.09N#

#F_2=4*0.03^2/0.27=0.013N#

#DeltaF=0.09-0.013=0.077N#