A model train with a mass of $2 kg$ is moving along a track at $2 (cm)/s$ . If the curvature of the track changes from a radius of $3 cm$ to $8 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-04-18T05:38:33

The centripetal force changes by $=0.017N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=2kg$

speed, $v=0.02ms^-1$

radius, $=r$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=2*0.02^2/0.03=0.0267N$

$F_2=2*0.02^2/0.08=0.01N$

$DeltaF=0.0267-0.01=0.0167N$

A model train with a mass of 2 kg2 kg is moving along a track at 2 (cm)/s2 (cm)/s. If the curvature of the track changes from a radius of 3 cm3 cm to 8 cm8 cm, by how much must the centripetal force applied by the tracks change?