How do you solve #sqrta+11=21# and check your solution?

Question

2222 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-18T05:48:33

#a=100#

Subtract #11# from both sides

#sqrtacancel(+11-11)=21-11#

#sqrta=10#

Square both sides

#(sqrta)^2=10^2#

#a=100#

To check the solution substitute this value (#100#) instead of #a# in the equation and see if it will give you #21#

#sqrtcolor(red)a+11=21#

#sqrtcolor(red)100+11=21#

#10+11=21#

#21=21#

So the solution is correct

Answer 2 · 2017-04-18T05:48:58

The answer is #a=100#

To get "a" by itself you want to subtract 11 from both sides:

#sqrta +11 -11 = 21 -11#

So now the equation is:

#sqrta=10#

Since you want to get "a" by itself, you want to now square both sides of the equation to get rid of the square root:

#sqrta ^2 = 10^2#

This is equal to:

#a=100#

If you have any questions, feel free to comment!