Question

Question #5a26c

Answer 1

`f^(-1)(x)=+-sqrt(2x+10)`

Explanation:

`y=1/2 x^2-5`

`"solve for x"`

`y+5=1/2x^2`

`2(y+5)=x^2`

`2y+10=x^2`

`x=+-sqrt(2y+10)`

`"substitute y=x"`

`y=+-sqrt(2x+10)`

`f^(-1)(x)=+-sqrt(2x+10)`