How do you solve #5x+y=5# and #10x + 3y = 20#?

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Answer 1 · 2017-04-23T09:21:25

See explanation.

The system is:

#{(5x+y=5),(10x+3y=20):}#

If you multiply the first equation by #-2# the oefficients of #x# will be opposite:

If you add both equations you get:

Now you can substitute the calcukated value to the first equation to calculate the value of #x#:

#5x=-5#

#x=-1#

Answer:

The solution is: