How do you find the product #(2a+9)(5a-6)#?
1 Answer
Explanation:
Notice that these are factors.
You can use the FOIL method or the Distributive Property .
What is FOIL ???
FOIL- First Outer Inner Last
#(2a+9)(5a-6)#
First: Multiply the first term in the first factor with the first term in the second factor. NB: both numbers are the first of both factors.
#2axx5a=10a^2#
Outer: Multipy the first term in the first factor with the last term in the second factor. NB: both numbers are the last of both factors.
#2axx-6=-12a#
Inner: Multiply the last term in the first factor with the first term in the second factor. NB: both numbers are innermost numbers.
#9xx5a=45a#
Last: Multiply the last term in the first factor with the last term in the second factor. NB: both numbers are the last numbers of each factor.
#9xx-6=-54#
Now add the numbers.
#10a^2+(-12a)+45a+(-54)#
#10a^2-12a+45a-54#
#10a^2+33a-54#
What is the Distributive Property ???
The distributive property is simply taking the first term in the first factor and multiplying it by the second term.
#2a(5a-6)=10a^2-12a#
Next, take the second term in the first factor and mutilply it by the second factor.
#9(5a-6)=45a-54#
Add the products
#(10a^2-12a)+(45a-54)#
#10a^2-12a+45a-54#
#10a^2+33a-54#
I hope this was well explained.
Follow the same steps and try to solve
You should get
All the best!