How do you find the product (2a+9)(5a-6)?
1 Answer
Explanation:
Notice that these are factors.
You can use the FOIL method or the Distributive Property .
What is FOIL ???
FOIL- First Outer Inner Last
(2a+9)(5a-6)
First: Multiply the first term in the first factor with the first term in the second factor. NB: both numbers are the first of both factors.
2axx5a=10a^2
Outer: Multipy the first term in the first factor with the last term in the second factor. NB: both numbers are the last of both factors.
2axx-6=-12a
Inner: Multiply the last term in the first factor with the first term in the second factor. NB: both numbers are innermost numbers.
9xx5a=45a
Last: Multiply the last term in the first factor with the last term in the second factor. NB: both numbers are the last numbers of each factor.
9xx-6=-54
Now add the numbers.
10a^2+(-12a)+45a+(-54)
10a^2-12a+45a-54
10a^2+33a-54
What is the Distributive Property ???
The distributive property is simply taking the first term in the first factor and multiplying it by the second term.
2a(5a-6)=10a^2-12a
Next, take the second term in the first factor and mutilply it by the second factor.
9(5a-6)=45a-54
Add the products
(10a^2-12a)+(45a-54)
10a^2-12a+45a-54
10a^2+33a-54
I hope this was well explained.
Follow the same steps and try to solve
You should get
All the best!