How do you find the product #(b+8)(b+2)#?

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Answer 1 · 2017-04-24T11:55:25

By multiplying, you can get #b^2+10b+16#

Multiply all terms #(b+8)(b+2)#
#b^2+2b+8b+16#
Arrange this as:

#b^2+10b+16#.

This is your answer.

Answer 2 · 2017-04-24T11:56:53

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(b) + color(red)(8))(color(blue)(b) + color(blue)(2))# becomes:

#(color(red)(b) xx color(blue)(b)) + (color(red)(b) xx color(blue)(2)) + (color(red)(8) xx color(blue)(b)) + (color(red)(8) xx color(blue)(2))#

#b^2 + 2b + 8b + 16#

We can now combine like terms:

#b^2 + (2 + 8)b + 16#

#b^2 + 10b + 16#