How do you solve #t/3-6> -4#?

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Answer 1 · 2017-04-26T12:51:21

See the solution process below:

Step 1) Add #color(red)(6)# to each side of the inequality to isolate the #t# term while keeping the inequality balanced:

#t/3 - 6 + color(red)(6) > -4 + color(red)(6)#

#t/3 - 0 > 2#

#t/3 > 2#

Step 2) Multiply each side of the inequality by #color(red)(3)# to solve for #t# while keeping the inequality balanced:

#color(red)(3) xx t/3 > color(red)(3) xx 2#

#cancel(color(red)(3)) xx t/color(red)(cancel(color(black)(3))) > 6#

#t > 6#