How do you graph #y=4/3sqrt(x)#?

2 Answers
Apr 28, 2017

Try different x values and plot accordingly

Explanation:

If you assign #x=1# you will get your function #y=4/3#

If you assign #x=2# you will get #y=1.886#

If you assign #x=3# you will get #y=2.309#

etc. On the negative side your function is not defined.

Now plot accordingly.

graph{(4/3)sqrtx [-3, 20, -2, 10]}

Apr 28, 2017

See explanation

Explanation:

Suppose the square root of #x# is #a#. Then the value of a may be positive or negative.

Example

#(-2)^2=(+2)^2=4#

So #sqrt(4)=+-2#

Thus #y=3/4 sqrt(x)" "# is really #y=+-3/4sqrt(x)#

If you wish the numbers to remain in the real domain #->RR# then

#y=+-3/4sqrt(-x)# is not permitted

That is: #x# is a squared value but the squared value must not itself be negative.
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Consequently the graph is split into 2 parts

First part: #" "y=+3/4sqrt(x)#
Second part #y=-3/4sqrt(x)#

Tony B