What is the amplitude and period of y=5/3sin(-2/3x)?

1 Answer
Apr 28, 2017

Amplitude=5/3
Period=3pi

Explanation:

Consider the form asin(bx-c)+d

The amplitude is |a|

and the period is {2pi)/|b|

We can see from your problem that
a=5/3 and b=-2/3

So for amplitude:

Amplitude=|5/3| ---> Amplitude=5/3

and for period:

Period= (2pi)/|-2/3| ---> Period= (2pi)/(2/3)

Consider this as a multiplication for better understanding...

Period= (2pi)/1-:2/3 ---> Period= (2pi)/1*3/2

Period= (6pi)/2 ---> Period=3pi