How do you solve #d/4+1>=-3#?
1 Answer
Apr 29, 2017
Explanation:
multiply ALL terms by 4 to eliminate the fraction.
#(cancel(4)xxd/cancel(4))+(4xx1)>=(4xx-3)#
#rArrd+4>= -12#
#"subtract 4 from both sides"#
#dcancel(+4)cancel(-4)>= -12-4#
#rArrd>= -16" is the solution"#
