How do you solve #6x^2+5x=1#?
2 Answers
Apr 29, 2017
Re-arranging we get:
We can write this as:
i.e.
=>
so,
:)>
Apr 29, 2017
Explanation:
#"subtract 1 from both sides and equate to zero"#
#6x^2+5x-1=1-1#
#rArr6x^2+5x-1=0#
#"using the a-c method of factorising"#
#"require the factors of the product " -6" which sum to +5"#
#"the factors are " +6, -1#
#rArr6x^2+6x-x-1=0larr" split 5x"#
#rArr6x(x+1)-1(x+1)=0larr" factor pairs"#
#(x+1)(6x-1)=0larr" factor out (x+1)"#
#(x+1)=0rArrx=-1#
#(6x-1)=0rArrx=1/6#
#rArrx=-1" or " x=1/6" are the solutions"#