How do you divide (-x^3+13x^2-x-5)/(x-4)x3+13x2x5x4?

2 Answers
Apr 29, 2017

-x^2+9x+35+135/(x-4)x2+9x+35+135x4

Explanation:

One way is to use the divisor as a factor in the numerator.

color(magenta)"add / subtract "" the terms that occur as a consequence"add / subtract the terms that occur as a consequence

"consider the numerator"consider the numerator

color(red)(-x^2)(x-4)color(magenta)(-4x^2)+13x^2-x-5x2(x4)4x2+13x2x5

=color(red)(-x^2)(x-4)color(red)(+9x)(x-4)color(magenta)(+36x)-x-5=x2(x4)+9x(x4)+36xx5

=color(red)(-x^2)(x-4)color(red)(+9x)(x-4)color(red)(+35)(x-4)color(magenta)(+140)-5=x2(x4)+9x(x4)+35(x4)+1405

rArr"quotient "=color(red)(-x^2+9x+35)" remainder "=135quotient =x2+9x+35 remainder =135

rArr(-x^3+13x^2-x-5)/(x-4)=-x^2+9x+35+135/(x-4)x3+13x2x5x4=x2+9x+35+135x4

Apr 29, 2017

(-x^2+9x+35)+135(x2+9x+35)+135

Explanation:

For this question, use synthetic division (if you don't know what that is, check this out: http://www.purplemath.com/modules/synthdiv.htm)

x-4 is linear, so we are allowed to use synthetic division.

Your synthetic division should look something like this:

4| -1 13 -1 -5

     -4   36  140

-1   9   35   135

So we get that (-x^3+13x^2-x-5)/(x-4) = (-x^2+9x+35)+135x3+13x2x5x4=(x2+9x+35)+135

Alternatively, you can use the long division to do this, though it will take a bit longer (https://www.mathsisfun.com/algebra/polynomials-division-long.html)

Hope that helps!