A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $36$ and the height of the cylinder is $6$ . If the volume of the solid is $108 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2017-04-30T07:14:36

The area of the base is $=18.8u^2$

Let $a=$ area of the base

Volume of cone is $V_(co)=1/3*a*h_(co)$

Volume of cylinder is $V_(cy)=a*h_(cy)$

Total volume

$V=V_(co)+V_(cy)$

$V=1/3ah_(co)+ah_(cy)$

$108pi=a(1/3*36+6)$

$108pi=a*18$

$a=108/18pi$

$a=6pi$

$a=18.8u^2$

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 36 36 and the height of the cylinder is 6 6 . If the volume of the solid is 108 pi108 pi, what is the area of the base of the cylinder?