Two rhombuses have sides with lengths of #6 #. If one rhombus has a corner with an angle of #pi/12 # and the other has a corner with an angle of #(5pi)/6 #, what is the difference between the areas of the rhombuses?

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Answer 1 · 2017-05-01T01:58:32

Difference in Area #~~ 8.6825 " units"^2#

Area of a rhombus is given by #a^2sinA#,
where #a# is its one side and #A# is an angle of the rhombus.

#=> "Area of Rhombus 1" = 6^2xxsin(pi/12)~~9.3175 " units"^2#

#=> "Area of Rhombus 2"=6^2xxsin((5pi)/6)~~18.0 " units"^2#

#=> "Difference in Area" ~~ 18.0-9.3175 ~~8.6825 " units"^2#