Question

A sample of ideal gas has a volume of 325 L at 13.60*C and 1.60 atm. What is the volume of the gas at 23.60°C and .994 atm?

Answer 1

`V_2=541*L`

Explanation:

`(P_1V_1)/T_1=(P_2V_2)/T_2`

And so we solve for `V_2=(P_1T_2V_1)/(P_2T_1)`

`=(1.60*atmxx296.75*Kxx325*L)/(0.994*atmxx286.8*K)`

`=541*L`.

Is my right arithmetic right? All care taken, but no responsibility accepted. Is it reasonable that the volume has increased so markedly? Why or why not?