A truck pulls boxes up an incline plane. The truck can exert a maximum force of $3,600 N$ . If the plane's incline is $(5 pi )/12$ and the coefficient of friction is $5/12$ , what is the maximum mass that can be pulled up at one time?

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Answer 1 · 2017-05-10T08:56:15

The mass is $=342.1kg$

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Resolving in the direction parallel to the plane $↗^+$

Let the force exerted by the truck be $=FN$

Let the frictional force be $=F_rN$

The coefficient of friction $mu=F_r/N$

The normal force is $N=mgcostheta$

Therefore,

$F=F_r+mgsintheta$

$=muN+mgsintheta$

$=mumgcostheta+mgsintheta$

$m=F/(g(mucostheta+sintheta))$

$=3600/(9.8(5/12*cos(5/12pi))+sin(5/12pi))$

$=342.1kg$

A truck pulls boxes up an incline plane. The truck can exert a maximum force of 3,600 N3,600 N. If the plane's incline is (5 pi )/12 (5 pi )/12 and the coefficient of friction is 5/12 5/12 , what is the maximum mass that can be pulled up at one time?