How do you write the equation #y-1/3=-2(x+1/3)# in slope intercept form?

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Answer 1 · 2017-05-11T12:54:52

Rearrange the equations so as to obtain 'y' as the only value on one side and simplify.

Slope-intercept form:

#y=mx+c#

So

#y = -2( x + 1/3) + 1/3#

#y = -2x - 2/3 + 1/3#

Therefore,

#y = -2x -1/3#

where the coefficient of 'x' is the slope and the value of 'c' is the y-intercept.