An object with a mass of #12 kg# is revolving around a point at a distance of #12 m#. If the object is making revolutions at a frequency of #14 Hz#, what is the centripetal force acting on the object?

Question

1199 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-14T12:40:28

The centripetal force is #=1114238.86N#

The centripetal force is

#F=mr omega^2#

The mass is #m=12kg#

The radius is #r=12m#

The angular velocity is #omega=2pif#

Where the frequency is #=f Hz#

So,

#omega=2*pi*14=28pi#

Therefore,

#F=12*12*(28pi)^2 N#

#=1114238.86N#