A charge of #12 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #32 J# to #18 J#, what is the voltage between points A and B?

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Answer 1 · 2017-05-17T17:38:19

The voltage is #=1.17V#

The potential difference between the points #A# and #B# is #=U#

Voltage =(Energy)/Charge

#U=(DeltaE)/Q#

#DeltaE=32-18=14J#

The charge is #Q=12C#

#1 V=(1J)/C#

#U=14/12=1.17V#