How do you graph #3x+2>2, 3x<=6#?

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Answer 1 · 2017-05-23T20:30:33

See below.

#3x+2>2#

Subtract both sides of the equation by 2

#3x>0#

Divide both sides of the equation by 3

#x>0#

graph{x>0 [-10, 10, -5, 5]}

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#3x <= 6#

Divide both sides of the equation by

#x <= 2# graph{x<=2 [-10, 10, -5, 5]}

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The answer is where these 2 graphs overlap.