How do you multiply #(2d+3)(2d–1)#?

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Answer 1 · 2017-05-28T14:46:45

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2d) + color(red)(3))(color(blue)(2d) - color(blue)(1))# becomes:

#(color(red)(2d) xx color(blue)(2d)) - (color(red)(2d) xx color(blue)(1)) + (color(red)(3) xx color(blue)(2d)) - (color(red)(3) xx color(blue)(1))#

#4d^2 - 2d + 6d - 3#

We can now combine like terms:

#4d^2 + (-2 + 6)d - 3#

#4d^2 + 4d - 3#