First, add #color(red)(10)# to each side of the equation to isolate the radical while keeping the equation balanced:
#sqrt((5y)/6) - 10 + color(red)(10) = 4 + color(red)(10)#
#sqrt((5y)/6) - 0 = 14#
#sqrt((5y)/6) = 14#
Next, square each side of the equation to eliminate the radical while keeping the equation balanced:
#(sqrt((5y)/6))^2 = 14^2#
#(5y)/6 = 196#
Now, multiply each side of the equation by #color(red)(6)/color(blue)(5)# to solve for #y# while keeping the equation balanced:
#color(red)(6)/color(blue)(5) xx (5y)/6 = color(red)(6)/color(blue)(5) xx 196#
#cancel(color(red)(6))/cancel(color(blue)(5)) xx (color(blue)(cancel(color(black)(5)))y)/color(red)(cancel(color(black)(6))) = 1176/5#
#y = 1176/5#
To check the solution we need to substitute #color(red)(1176/5)# for #color(red)(y)#, calculate each side of the equation and ensure the two results are equal:
#sqrt((5color(red)(y))/6) - 10 = 4# becomes:
#sqrt((5 xx color(red)(1176/5))/6) - 10 = 4#
#sqrt((color(red)(cancel(color(black)(5))) xx color(red)(1176/color(black)(cancel(color(red)(5)))))/6) - 10 = 4#
#sqrt(1176/6) - 10 = 4#
#+-sqrt(196) - 10 = 4#
#+-14 - 10 = 4#
#4 = 4# or #-24 = 4#
The #-14# result of the square root is extraneous.
Therefore, #4 = 4# and the solution is shown to be correct.