How do you find the intercepts, vertex and graph #f(x)=2x^2#?

1 Answer
Ryan
May 31, 2017

Well, this is simply a dilation of the standard #f(x)=x^2# parabola, so there isn't much to find!

Explanation:

For any parabola #f(x)=x^2#, we know that it turns at the point #(0,0)# therefore its intercepts are there too. The dilation of #2# from the x-axis simply means that the graph is 'narrower'.

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