Question

How do you find the period of `y=2 tan(3pi(x) +4)`?

Answer 1

When given a function of the form:

`y = Atan(Bx + C) + D`

The period is `P = pi/B`

Explanation:

Given: `y=2 tan(3pi(x) +4)`

`P = pi/(3pi)`

`P = 1/3`