How do you solve $2 x^{2} - 17 x + 30 = 0$ $2x^2-17x+30=0$ ?

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Answer 1 · 2017-06-05T21:05:45

See below.

We factor.

$2 x^{2} - 17 x + 30 = 0$ $2x^2-17x+30=0$

$2 x^{2} - 12 x - 5 x + 30 = 0$ $2x^2-12x-5x+30=0$

$2 x (x - 6) - 5 (x - 6) = 0$ $2x(x-6)-5(x-6)=0$

$(2 x - 5) (x - 6) = 0$ $(2x-5)(x-6)=0$

So,

$x = \frac{5}{2}, 6$ $x=5/2,6$ .

How do you solve 2x^2-17x+30=02x2−17x+30=02x^2-17x+30=0?