Question

How do you multiply `3x ^ { 3} y ^ { 4} \cdot - 2x ^ { 4} y ^ { 3} \cdot - y x ^ { 2}`?

Answer 1

`3x^3y^4*-2x^4y^3*-yx^2=6x^9y^8`

Explanation:

As there are two negatives in the product of three monomials, the product would be positive.

Further on multiplication, powers of same base are added as `a^mxxa^n=a^((m+n))`

Hence `3x^3y^4*-2x^4y^3*-yx^2`

= `(3xx2xx1)x^((3+4+2))y^((4+3+1))`

= `6x^9y^8`