How do you find the range and domain of $sin (arctan x)$ $sin(arctan x)$ ?

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How do you find the range and domain of $sin (arctan x)$ $sin(arctan x)$ ?

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Answer 1 · 2017-06-11T10:03:23

Range for $sin (arctan x)$ $sin(arctanx)$ is $[- 1, 1]$ $[-1,1]$ , and domain is $(- \infty, \infty)$ $(-oo,oo)$ .

Explanation:

$arctan x$ $arctanx$ is always from $- \frac{π}{2}$ $-pi/2$ to $\frac{π}{2}$ $pi/2$ , but here $x$ $x$ can take any value from $(- \infty . \infty)$ $(-oo.oo)$ , which is domain for $sin (arctan x)$ $sin(arctanx)$ .

But $sin (arctan x)$ $sin(arctanx)$ can take values only from $[- 1, 1]$ $[-1,1]$

Hence range for $sin (arctan x)$ $sin(arctanx)$ is $[- 1, 1]$ $[-1,1]$ .

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How do you find the range and domain of $sin (arctan x)$ $sin(arctan x)$ ?

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Explanation:

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How do you find the range and domain of sin(arctan x)sin(arctanx)sin(arctan x)?

1 Answer

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How do you find the range and domain of $sin (arctan x)$ $sin(arctan x)$ ?