Two opposite sides of a parallelogram each have a length of #8 #. If one corner of the parallelogram has an angle of #(7 pi)/8 # and the parallelogram's area is #54 #, how long are the other two sides?

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Answer 1 · 2017-06-14T12:23:43

The other sides are #=17.64#

Let the other side of the parallelogram be #b#

The area of the parallelogram is

#8bsin(7/8pi)=54#

Then,

#b=54/(8sin(7/8pi))#

#=17.64#