Question

If a volume of `1.7*atm` at `26.0*L` is compressed to `10.7*L`, what is the new pressure?

Answer 1

Well, we use old Boyle's Law.........

Explanation:

Which holds that for a given mass of gas at constant temperature, then `PV=k`, where `k` is some constant...........and so under equivalent conditions of temperature......

`P_1V_1 = P_2V_2`................

And here we solve for `P_2=(P_1V_1)/V_2`

`=(1.7*atmxx26.0*L)/(10.7*L)`

`=4.1*atm.........`

Why is it reasonable that pressure has increased?