Question

How do you long divide `(16y^(2)-8y-8) /( 4y-2)`?

Answer 1

`(16y^2-8y-8)/(4y-2)=4y-4/(2y-1)`

Explanation:

`(16y^2-8y-8)/(4y-2)`

`=(4y(4y-2)-8)/(4y-2)`

`=(4y(4y-2))/(4y-2) -8/(2(2y-1))`

`=4y-4/(2y-1)`