Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `42 J` to `21 J`, what is the voltage between points A and B?

Answer 1

The voltage between `A` and `B` is `=3.5V`

Explanation:

The charge is `Q=6C`

The variation in the charge electric potential is

`DeltaW=42-21=21J`

The voltage is `DeltaV=(DeltaW)/Q=21/6=3.5V`