Question

How do you solve `2x^2 + 3x - 14 = 0`?

Answer 1

2, and `- 7/2`

Explanation:

`2x^2 + 3x - 14 = 0`
Use new Transforming Method.
Transformed equation:
`y' = x^2 + 3x - 28 = 0`
Proceeding: find 2 real roots of y', then, divide them by a = 2.
Find 2 real roots, knowing sum (-b = -3) and product (ac = - 28). They are: 4 and -7 (because sum = -3 and product = - 28).
Back to original y, the 2 real roots are:
`x1 = 4/a = 4/2 = 2`, and `x2 = - 7/a = - 7/2 = - 7/2`