What are the solutions to the equation #x^2+2x+2=0#?
1 Answer
Jul 5, 2017
Explanation:
#"check the value of the "color(blue)"discriminant"#
#"with " a=1,b=2,c=2#
#Delta=b^2-4ac=4-8=-4#
#"since " Delta<0" the equation has no real solutions"#
#"solve using the "color(blue)"quadratic formula"#
#x=(-2+-sqrt(-4))/2=(-2+-2i)/2#
#rArrx=-1+-i" are the solutions"#
