Question

What is the axis of symmetry and vertex for the graph `y=x^2 +2x -5`?

Answer 1

See explanation.

Explanation:

To calculate the vertex of a parabola you use the following formulas:

`p=(-b)/(2a)` ##

and

`q=(-Delta)/(4a)`

where

`Delta=b^2-4ac`

Here we have:

`p=(-2)/2=-1`

`Delta=(2)^2-4*1*(-5)=4+20=24`

`q=-24/4=-6`

The axis of symetry of a parabola is `x=p`. Here it is: `x=-1`

Answer:
The vertex is `V=(-1,-6)`. The axis of symetry: `x=-1`