An object with a mass of $2 kg$ is on a surface with a kinetic friction coefficient of $2$ . How much force is necessary to accelerate the object horizontally at $12 m/s^2$ ?

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Answer 1 · 2017-07-11T08:08:06

The force is $=63.2N$

The coefficient of friction is

$mu_k=F_r/N$

The frictional force is $F_r$

The normal force is $N=mg$

The net force on the object is $=F$

$F-F_r=ma$

$F-mu_kN=ma$

$F=mu_kmg+ma=m(mu_kg+a)$

$mu_k=2$

$a=12ms^-2$

$m=2kg$

Therefore,

$F=2(2*9.8+12)=63.2N$

An object with a mass of 2 kg2 kg is on a surface with a kinetic friction coefficient of 2 2 . How much force is necessary to accelerate the object horizontally at 12 m/s^212 m/s^2?