Question

How do you find the roots, real and imaginary, of `y=2x² -452x-6` using the quadratic formula?

Answer 1

`x=113+-2sqrt(3193)`

Explanation:

`y=2x^2-452-6`

Let `y=0`

`2x^2-452-6=0`

`x^2-226-3=0`

`x=(226+-sqrt(226^2-4(1)(3)))/2=(226+-4sqrt(3193))/2`

`=113+-2sqrt(3193)`