How do you find period, amplitude, phase shift and midline of #y = 3 + 2cos(x + (pi/4))#?
1 Answer
Jul 15, 2017
Explanation:
#"the standard form of the "color(blue)"cosine function"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#
#"where amplitude "=|a|," period "=(2pi)/b#
#"phase shift "=-c/b," vertical shift "=d#
#"here "a=2,b=1,c=pi/4" and "d=3#
#rArr"amplitude "=|2|=2," period "=(2pi)/1=2pi#
#"phase shift "=-(pi/4)/1=-pi/4#
#"maximum value "=3+2=5#
#"minimum value "=3-2=1#
#rArr"midline "y=1/2(5+1)=3#