Question

How do you graph `2x+3y=3` using intercepts?

Answer 1

Please see below.

Explanation:

`x`-intercept is where `y=0` i.e. `2x+3xx0=3` or `2x=3` and `x=1.5` i.e. line passes through `(1.5,0)`.

`y`-intercept is where `x=0` i.e. `2xx0+3y=3` or `3y=3` and `y=1` i.e. line passes through `(0,1)`.

Now join `(1.5,0)` and `(0,1)` to get the line.

graph{(2x+3y-3)((x-1.5)^2+y^2-0.003)(x^2+(y-1)^2-0.003)=0 [-1.917, 3.082, -0.77, 1.73]}

Tip - If intercept on `x`-axis is`a` and intercept on `y`-axis is `b`, equation of line is `x/a+y/b=1`.