If a projectile is shot at an angle of #pi/12# and at a velocity of #2 m/s#, when will it reach its maximum height??

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Answer 1 · 2017-07-19T16:38:51

The time to reach the greatest height is #=0.053s#

Resolving in the vertical direction #uarr^+#

The initial velocity is #u_y=vsintheta=2*sin(1/12pi)#

The Acceleration is #a=-g#

At the maximum height, #v=0#

We apply the equation of motion

#v=u+at#

to calculate the time to reach the greatest height

#0=2sin(1/12pi)-g*t#

#t=2/(g)*sin(1/12pi)#

#=0.053s#