Question

What would happen if there was no hybridization in `"CH"_4`?

Answer 1

The answer would take a `90^@` shape, even more contracted than water.

Explanation:

This structure would not happen because `CH_4`, methane, requires 4 bonds.

The pure `2s^2` electrons would be nonbonding, so they have no ability to form more bonds. Then, the pure `2p` orbitals would only form `:CH_2` (with an empty `2p_z`), not `CH_4`.