How do you find the y intercept, axis of symmetry and the vertex to graph the function #f(x)=x^2+12x+36#?
1 Answer
Jul 23, 2017
Explanation:
#"factorising f(x) gives"#
#f(x)=(x+6)^2#
#"the equation of a parabola in "color(blue)"vertex form"# is.
#•color(white)(x)y=a(x-h)^2+k#
where (h , k ) are the coordinates of the vertex and a is a constant.
#y=(x+6)^2+0" is in this form"#
#rArrcolor(magenta)"vertex "=(-6,0)#
#"the axis of symmetry passes through the vertex , is vertical"#
#"with equation "#
#"axis of symmetry is "x=-6#
#"to find y-intercept set x = 0 in the equation"#
#y=(0+6)^2=36larrcolor(red)" y-intercept"#
