Question

How do you simplify `\frac { ( 2x y ^ { 4} ) ^ { 3} } { 2x y ^ { 5} \cdot y x ^ { 5} }`?

Answer 1

`(2xy^4)^3/(2xy^5*yx^5)=(4y^6)/x^3`

Explanation:

`(2xy^4)^3/(2xy^5*yx^5)`

= `(2^3xx x^3(y^4)^3)/(2x^(1+5)y^(5+1))`

= `(8x^3y^12)/(2x^6y^6)`

= `(cancel8^4y^(12-6))/(cancel2x^(6-3))`

= `(4y^6)/x^3`