Question

What is the volume occupied by a gas that has a `1000*mL` at `396*K` under `2*atm` pressure, that is cooled to `200*K`, and the pressure decreased to `0.5*atm`?

Answer 1

`V_2~=8000*mL` as required........

Explanation:

`(P_1V_1)/T_1=(P_2V_2)/T_2`, for a given quantity of gas according to the combined gas law.....

We solve for `V_2=(P_1V_1T_2)/(P_2T_1)=??*mL`

`(2*atm*1000*mL*396*K)/(0.5*atm*200*K)=??*mL`....

Clearly we get an answer with units of volume as required. Do you agree? And remember `1*L-=1000*mL`.