A model train, with a mass of #3 kg#, is moving on a circular track with a radius of #2 m#. If the train's rate of revolution changes from #5/8 Hz# to #3/4 Hz#, by how much will the centripetal force applied by the tracks change by?

Question

1233 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-26T06:34:29

The centripetal force change by #=3.7N#

The centripetal force is

#F=mr omega^2#

The mass is #m=3kg#

The radius #r=2m#

The change in angular velocity is

#Delta omega=(3/4-5/8)*2pi=(1/4pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=3*2*(1/4pi)^2#

#=3.7N#