How do you use the important points to sketch the graph of #y=x^2 - x - 12 = 0#?

1 Answer
Jul 26, 2017

Factorise first

Explanation:

If you factorise this equation, you will get:

#(x-4)(x+3)=0#

Putting each bracket equal to zero gives #x=4 or x=-3# as your x intercepts (where the graph crosses the x axis).

If you put #x=0#, this will give you your y intercept which in this case is #-12# (#0^2-0-12#).

As it's a quadratic (power of 2 in the equation) it will be a smooth, U-shaped curve going through the above points.