How do you find the amplitude, period, phase shift for #y=y=1/8sinx#?

1 Answer
Jul 28, 2017

#1/8,2pi,0#

Explanation:

#"the standard form of the "color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" vertical shift "=d#

#"here "a=1/8,b=1,c=d=0#

#rArr"amplitude "=|1/8|=1/8," period"=2pi#

#"there is no phase/vertical shift"#